this code was inspired from people in forum when ask me an algorithm. this is an implementation from the algorithm. It's only for fun and for wasting a time. also to learn programming language. I hope this's not the last.
Bash script version
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start here
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#!/bin/bash
echo -n "Your input: "; read input
let temp=$input/2
let temp=$temp+1
let count=0
let i=1
echo $temp
while ((i<=input))
do
let j=1
let left=1
let right=$input
if [[ $i -le $temp ]]; then
let count=$count+1
elif [[ $i -gt $temp ]]; then
let count=$count-1
fi
while ((j<=input))
do
if [[ $left -le $count ]]; then
echo -n "$left "
elif [[ $right -le $count ]]; then
echo -n "$right "
else
echo -n "$count "
fi
let left=$left+1
let right=$right-1
let j=$j+1
done
let i=$i+1;
echo ""
done
C Version
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Start here
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#filename: funcode.c
int main ()
{
int input, temp=0, count=0;
int i,j,left,right;
printf ("Your input: ");scanf("%d",&input);
printf ("Dimention: %d \n",input);
temp=(input/2) + 1;
printf("temp: %d \n",temp);
for (i=1; i<=input; i++)
{
j=1;
left=1;
right=input;
if (i <= temp)
count++;
else if (i> temp)
count--;
for (j=1; j<=input; j++)
{
if (left <= count)
printf("%d ",left);
else if (right <= count)
printf("%d ",right);
else
printf("%d ",count);
left++;
right--;
}
printf("\n");
}
return 0;
}
An output is here:
mine@unique:~$ ./funcode
Your input: 5
Dimention: 5
temp: 3
1 1 1 1 1
1 2 2 2 1
1 2 3 2 1
1 2 2 2 1
1 1 1 1 1
mine@unique:~$
